I kept trying to make this problem harder than it actually was, but ultimately a simple greedy solution worked just fine.

I would have saved myself a lot of time by actually solving the problem before attempting to optimize. C’est la vie!

Investigating combinations of English currency denominations.

def count_coins coins, target, last_coin = 0 return 1 if target == 0 total = 0 coins.each do |c| next if c < last_coin total += count_coins(coins, target - c, c) if (target >= c) end total end puts count_coins( [1,2,5,10,20,50,100,200], 200 )